x4+4x3+3x2-2(x+3)因式分解
问题描述：
x4+4x3+3x2-2(x+3)因式分解
答
x=1
x4+4x3+3x2-2x-6=0
x4+4x3+3x2-2x-6
=x4-x3+5x3-5x2+8x2-8x+6x-6
=(x-1)(x3+5x2+8x+6)
x=-3
x3+5x2+8x+6=-27+45-24+6=0
x4+4x3+3x2-2x-6
=x4-x3+5x3-5x2+8x2-8x+6x-6
=(x-1)(x3+5x2+8x+6)
=(x-1)(x3+3x2+2x2+2x+6x+6)
=(x-1)(x+3)(x2+2x+6)
答
=x^2(x^2+4x+3)-2(x+3)
=x^2(x+3)(x+1)-2(x+3)
=(x+3)(x^3+x^2-2)
答
x4+4x3+3x2-2(x+3)
=> x²(x²+4x+3)-2(x+3)
=> x²(x+3)(x+1)-2(x+3)
=>(x+3)(x²(x+1)-2)
=>(x+3)(x³+x²-2)
答
x4+4x3+3x2-2(x+3)=x²（x²+4x+3)-2(x+3)
=x²(x+3)(x+1)-2(x+3)
=(x+3)[x²（x-1）-2]