x2+3x+2分之x-1减去x2-x-2分之6减去x2-4分之x-10x-1/x2+3x+2减去6/x2-x-2减去x-10/x2-4
问题描述：
x2+3x+2分之x-1减去x2-x-2分之6减去x2-4分之x-10
x-1/x2+3x+2减去6/x2-x-2减去x-10/x2-4
答
多种理解方法
答
x2+3x+2分之x-1减去x2-x-2分之6减去x2-4分之x-10
=(x-1)/(x+1)(x+2)-6/(x-2)(x+1)-(x-10)/(x+2)(x-2)
={(x-1)2(x-2)-6(x+2)(x-1)-(x-10)(x2-1)}/(x2-1)(x2-4)
=-8x/(x2-1)(x2-4)
答
=(x-1)/[(x+1)(x+2)]-6/[(x+1)(x-2)]-(x-10)/[(x-2)(x+2)] =[(x-1)(x-2)-6(x+2)-(x-10)(x+1)]/[(x+1)(x+2)(x-2)]=[(x2-3x+2)-(6x+12)-(x2-9x-10)]/[(x+1)(x+2)(x-2)]=[x2-3x+2-6x-12-x2+9x+10]/[(x+1)(x+2)(x-2)]=0/...
答
什么啊，相当混乱的说法，有很多理解方法