x2+3x+2分之x-1减去x2-x-2分之6减去x2-4分之x-10
问题描述：
x2+3x+2分之x-1减去x2-x-2分之6减去x2-4分之x-10
x-1/x2+3x+2减去6/x2-x-2减去x-10/x2-4
答
=(x-1)/[(x+1)(x+2)]-6/[(x+1)(x-2)]-(x-10)/[(x-2)(x+2)] =[(x-1)(x-2)-6(x+2)-(x-10)(x+1)]/[(x+1)(x+2)(x-2)]=[(x2-3x+2)-(6x+12)-(x2-9x-10)]/[(x+1)(x+2)(x-2)]=[x2-3x+2-6x-12-x2+9x+10]/[(x+1)(x+2)(x-2)]=0/...