已知a、b满足√2a+8+丨b-√3丨=0,解关于x的方程（a+2）x+b=a-1
问题描述：
已知a、b满足√2a+8+丨b-√3丨=0,解关于x的方程（a+2）x+b=a-1
答
2a +8 = 0 b - √3 = 0 ==> a = -4 b = √3 (a +2)x + b^2 = a -1 ==> (-4 +2)x + (√3)^2 = (-4) -1 ==> -2x + 3 = -5 ==> -2x = -8 ==> x =4