∫dx/[cos^2(2x+兀/4)]
问题描述:
∫dx/[cos^2(2x+兀/4)]
答
哈哈哈你的pi写的太好玩了
∫dx/[cos^2(2x+π/4)]
=∫dx/[1/2cos(4x+π/2)+1/2]
=∫dx/[-1/2sin(4x)+1/2]
=1/8*cos(4x)+C (C为常数)