m/x²-y²=2xy-y²/2x-y+x-y/x+y,则m=?回答满意50分m/(x²-y²)=(2xy-y²)/(2x-y)+(x-y)/(x+y),则m=?

问题描述:

m/x²-y²=2xy-y²/2x-y+x-y/x+y,则m=?
回答满意50分
m/(x²-y²)=(2xy-y²)/
(2x-y)+(x-y)/(x+y),则m=?

m/(x²-y²)=(2xy-y²)/(2x-y)+(x-y)/(x+y)
m/(x²-y²)=y+(x-y)/(x+y)
m/(x²-y²)=y(x-y)²/(x²-y²)+(x-y)²/(x²-y²)
m=(y+1)(x-y)²

m/(x²-y²)=(2xy-y²)/(2x-y)+(x-y)/(x+y)
m/(x²-y²)=y(2x-y)/(2x-y)+(x-y)/(x+y)
m/(x²-y²)=y+(x-y)/(x+y)
m/(x²-y²)=y(x+y)(x-y)/[(x+y)(x-y)]+(x-y)(x-y)/[(x+y)(x-y)]
m/(x²-y²)=[y(x+y)(x-y)+(x-y)²]/(x²-y²)
m=y(x+y)(x-y)+(x-y)²=(x-y)(xy+y²+x-y).