[U/(16+R')]2R'=[U/(16+R'/4)]2R'/4 怎么解“2”是指数
问题描述:
[U/(16+R')]2R'=[U/(16+R'/4)]2R'/4 怎么解
“2”是指数
答
[U/(16+R')]2R'=[U/(16+R'/4)]2R'/4 约掉U^2,R'开方得 :16+R'=2(16+R'/4)=32+0.5R'
R'=32