x+y+z=2,x-z=-2,y+z=1

问题描述:

x+y+z=2,x-z=-2,y+z=1

2-1=x=1
1-z=-2
z=3
3+y=1
y=-2
x=1 y=-2 z=3

x+(y+z)=2,x=2-1=1,x-z=-2,z=1+2=3,y=1-3=-2

将x=z-2,y=1-z代入x+y+z=2得
z=3
x=1
y=-2

z=-1
x=-2
y=0