(1) X^3+7X+8 (2) 2a^2+b^2+3ab+a-b-6
问题描述:
(1) X^3+7X+8
(2) 2a^2+b^2+3ab+a-b-6
答
(1)原式=x^3+1+7(x+1)=(x+1)(x^2-x+1)+7(x+1)=(x+1)(x^2-x+8)
(2)原式=(2a+b-3)(a+b+2)
答
(1)(x+1)(x^2-x+8)
(2)(2a+b-3)(a+b+2)