已知函数f(x)=根号2sin(x+π/4)当x0属於(0,3π/4)且f(x0)=1时,求x0的值
问题描述:
已知函数f(x)=根号2sin(x+π/4)当x0属於(0,3π/4)且f(x0)=1时,求x0的值
答
f(x0)=√2sin(x0+π/4)=1
则sin (x0+π/4)= 1/2
x0∈(0,3π/4)
x0+π/4=5π/6
x0=7π/12