sin48°cos18°-sin42°cos72°=?,
问题描述:
sin48°cos18°-sin42°cos72°=?,
答
sin48°cos18°-sin42°cos72° =sin48°cos18°-cos48°sin18°(sinA=cos(90°-A)) =sin(48°-18°) =sin30° =1/2
sin48°cos18°-sin42°cos72°=?,
sin48°cos18°-sin42°cos72° =sin48°cos18°-cos48°sin18°(sinA=cos(90°-A)) =sin(48°-18°) =sin30° =1/2