圆内接正七边形A1A2A3A4A5A6A7,证明:1/A1A2=1/A1A3+1/A1A4

问题描述:

圆内接正七边形A1A2A3A4A5A6A7,证明:1/A1A2=1/A1A3+1/A1A4

觉得有点怪

我回答过了:
因为是正七边形,所以A1=A2=A3=A4
所以1/a1a2=1/a1a3=1/a1a4