x2-2x+2y-y2因式分解
问题描述：
x2-2x+2y-y2因式分解
答
x2-2x+1-1+2y-y2=（x-1）^2-(y-1)^2 =(x-y)(x+y-2)
答
=[4(x2+x-2)2-(x-3)2]* {[2(x+2)(x-1)]2+(x-3)2} =(2x2+3x-7)(2x-1)(x+1) {[2(x+2)(x-1)]2+(x-3)2} 4xy+2y-
答
（x-y）（x+y-2）
答
x2-2x+2y-y2
=x²-y²-2x+2y
=(x+y)(x-y)-2(x-y)
=(x-y)(x+y-2)
答
x2-2x+2y-y2
=﹙x＋y﹚﹙x－y﹚－2﹙x－y﹚
=﹙x－y﹚﹙x＋y－2﹚
答
x2-y2-2(x-y)=(x-y)(x+y)-2(x-y)=(x-y)(x+y-2)