因式分解(x2+1)y2-x2-1
问题描述:
因式分解(x2+1)y2-x2-1
答
(x2+1)(y-1)(y+1)
答
(2x+1)2y-2x-1
=4xy+2y-2x-1
=4xy-2x+2y-1
=2x(2y-1)+(2y-1)
=(2x+1)(2y-1)
答
(x2+1)y2-x2-1
=x2y2+y2-x2-1
=(x2y2-x2)+(y2-1)
=x2(y2-1)+(y2-1)
=(x2-1)(y2-1)
=(x+1)(x-1)(y+1)(y-1)
答
(X2+1)(Y2-1)