¼²÷×(-½)4次方×(-1)¹ºº-(1又3/8+2又1/3-3又3/4)×24 计

问题描述:

¼²÷×(-½)4次方×(-1)¹ºº-(1又3/8+2又1/3-3又3/4)×24 计

(1/4)^2÷(-1/2)^4×(-1)^100
-(1+3/8+2+1/3-3-3/4)×24
=1/16×16×1-(3/8+1/3-3/4)×24
=1-(9+8-18)
=1+1
=2.