已知-x²y=2,求-xy(x五次幂y²-x³y+2x)的值
问题描述:
已知-x²y=2,求-xy(x五次幂y²-x³y+2x)的值
答
原式=-xy((x²y)²x-x²yx+2x)=-xy((-2)²x+2x+2x)=-8x²y=16
已知-x²y=2,求-xy(x五次幂y²-x³y+2x)的值
原式=-xy((x²y)²x-x²yx+2x)=-xy((-2)²x+2x+2x)=-8x²y=16