计算(i+1)^2=?,i^2013=?,(i+1)/(1-i)=?
问题描述:
计算(i+1)^2=?,i^2013=?,(i+1)/(1-i)=?
答
(i+1)=i+2i+1=-1+2i+1=2i i^2013=(i^4)^503×i=i (i+1)/(i-1)=(i+1)/(i-1)=2i/(-2)=-i
计算(i+1)^2=?,i^2013=?,(i+1)/(1-i)=?
(i+1)=i+2i+1=-1+2i+1=2i i^2013=(i^4)^503×i=i (i+1)/(i-1)=(i+1)/(i-1)=2i/(-2)=-i