计算:(2x+3y+2)(2x-3y+6)

问题描述:

计算:(2x+3y+2)(2x-3y+6)

(2x+3y+2)(2x-3y+6)
=2x(2x-3y+6)+3y(2x-3y+6)+2(2x-3y+6)
=4x-6xy+12x+6xy-9y2+18y+4x-6y+12
=20x-9y2+12y+12

(2x+3y+2)(2x-3y+6)
=[(2x+4)+(3y-2)]*[(2x+3)-(3y-2)]
=(2x+4)^2-(3y-2)^2
=(4x^2+16x+16)-(9y^2-12y+4)
=4x^2-9y^2+16x+12y+12