((x+2/2x^2-3x)-(x^2+2x/2x^2+x-6))/((1/2)-(1/4x-6))
问题描述：
((x+2/2x^2-3x)-(x^2+2x/2x^2+x-6))/((1/2)-(1/4x-6))
答
((x+2/2x^2-3x)-(x^2+2x/2x^2+x-6))/((1/2)-(1/4x-6))
=[(x+2)/x(2x-3)-x(x+2)/(2x-3)(x+2)]/[(2x-4)/(4x-6)]
=[(x+2)/x-x]/(x-2)
=(-x^2+x+2)/x(x-2)
=-(x-2)(x+1)/x
=-(x+1)/x