已知√2x+y-4+(4x-y-2)²=0,求式子4分之1(-3xy²)²的值
问题描述:
已知√2x+y-4+(4x-y-2)²=0,求式子4分之1(-3xy²)²的值
答
2x+y-4=0
4x-y-2=0
x=1,y=2
4分之1(-3xy²)²
=36