[(x+y)^2n]^4/(-x-y)^(2n+1)计算

分类: 作业答案 • 2022-07-10 22:11:58

问题描述：

[(x+y)^2n]^4/(-x-y)^(2n+1)计算
快

答

[(x+y)^2n]^4/(-x-y)^(2n+1)
=[(x+y)^2n]^4/-(x+y)^(2n+1)
=-(x+y)^[8n-(2n+1)]
=-(x+y)^(6n-1)