因式分解：x5-3x4+2x3-x2+3x-2

分类: 作业答案 • 2022-07-09 17:43:19

问题描述：

答

x5-3x4+2x3-x2+3x-2
=x3(x2-3x+2)-(x2-3x+2)
=(x3-1)(x-2)(x-1)
=(x-1)2(x-2)(x2+x+1)

答

x5-3x4+2x3-x2+3x-2
=x3(x2-3x+2)-(x2-3x+2)
=(x3-1)(x2-3x+2)
=(x-1)(x2-x+1)(x-1)(x-2)
=(x-1)的平方(x2-x+1)(x-2)

答

x5-3x4+2x3-x2+3x-2
=x^3(x^2-3x+2)-(x^2-3x+2)
=(x^3-1)(x^2-3x+2)
=(x-1)(x^2+x+1)(x-1)(x-2)
=(x-1)^2(x-2)(x^2+x+1)