计算：sin(-1200°）·cos1230°+cos（-1020°）sin(-1050°）+tan1305°
问题描述：
计算：sin(-1200°）·cos1230°+cos（-1020°）sin(-1050°）+tan1305°
答
sin(-1200+360*4)*cos(1230-360*3)+cos(-1020+3*360)*-sin(-1050+360*3)+tan(1305-180*7)=sin(240)*cos(150)+cos(60)*sin(30)+tan(45)=[-sin(60)]*[-cos(30)]+cos(60)*sin(30)+tan(45)=-((根号)3)/2*-((根号)3)/2+1/...