化简求值(2sin80`-cos70`)/cos20`
问题描述：
化简求值(2sin80`-cos70`)/cos20`
答
(2sin80-cos70)/cos20
=[2sin(60+20)-sin20]/cos20
=[2(sin60cos20+cos60sin20)-sin20]/cos20
=(2sin60cos20+2cos60sin20-sin20)/cos20
因为cos60=1/2
所以,原式=(2sin60cos20+2×1/2sin20-sin20)/cos20
=(2sin60cos20+sin20-sin20)/cos20
=(2sin60cos20)/cos20
=2sin60
=2×√3/2
=√3 [表示根号3]