1、当a+b+c=0时,求证:a3+b3+c3=3abc2、①(x+y)(___________)=x4-y4②(x-y)(__________)=x4-y4③(x+y)( ___________)=x5+y5④(x-y)(__________)=x5-y5 3、己知a+b=1, 求证:a3+b3-3ab=14、己知a2=a+1,求代数式a5-5a+2的值5、求证:233+1能被9整除
问题描述:
1、当a+b+c=0时,求证:a3+b3+c3=3abc
2、①(x+y)(___________)=x4-y4②(x-y)(__________)=x4-y4
③(x+y)( ___________)=x5+y5④(x-y)(__________)=x5-y5
3、己知a+b=1, 求证:a3+b3-3ab=1
4、己知a2=a+1,求代数式a5-5a+2的值
5、求证:233+1能被9整除
答