计算:2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1
问题描述:
计算:2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1
答
2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1=(3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1=(3^4-1)(3^4+1)(3^8+1)(3^16+1)+1=(3^8-1)(3^8+1)(3^16+1)+1=(3^16-1)(3^16+1)+1=3^32-...