∫sinx^2cos^3dx
问题描述:
∫sinx^2cos^3dx
答
∫ sin²xcos³x dx
= ∫ sin²xcos²x d(sinx)
= ∫ sin²x(1 - sin²x) d(sinx)
= ∫ (sin²x - sin⁴x) d(sinx)
= (1/3)sin³x - (1/5)sin⁵x + C