计算(3+1)(3^2+1)(3^4+1)……(3^32+1) 要步骤
问题描述:
计算(3+1)(3^2+1)(3^4+1)……(3^32+1) 要步骤
答
(3+1)(3^2+1)(3^4+1)……(3^32+1)
=[(3-1)(3+1)(3^2+1)(3^4+1)……(3^32+1)]/2
=[(3^2-1)(3^2+1)(3^4+1)……(3^32+1)]/2
=………………
=(3^64-1)/2