(lg2^1/2+lg3-lg10^1/2)/lg1.

问题描述:

(lg2^1/2+lg3-lg10^1/2)/lg1.

原式=[1/2lg2+1/2lg9-1/2lg10]/lg1.8 =[1/2lg(2×9÷10)]/lg1.8 =1/2lg1.8/lg1.8 =1/2