f(x)=cos(x +圆周率/2)cos(x +圆周率/6)的最小正周期是多少?
问题描述:
f(x)=cos(x +圆周率/2)cos(x +圆周率/6)的最小正周期是多少?
答
f(x) =cos(x+π/2)cos(x+π/6)
= (cos( 2x+2π/3)+ cos(π/3))/2
=cos( 2x+2π/3) /2 + 1/4
最小正周期 = π