分解因式:[(2x^2-(x+y)(x-y)][(z-x)(x+z)-(-y-z)(z-y)]+z,其中x=‐1,y=1/2,z=‐3/4
问题描述：
分解因式:[(2x^2-(x+y)(x-y)][(z-x)(x+z)-(-y-z)(z-y)]+z,其中x=‐1,y=1/2,z=‐3/4
答
[(2x^2-(x+y)(x-y)][(z-x)(x+z)-(-y-z)(z-y)]+z=(2x^2-x^2+y^2)[z^2-x^2+z^2-y^2]+z=(x^2+y^2)(2z^2-x^2-y^2)+z=(1+1/4)(2*9/16-1-1/4)-3/4=5/4*(-1/8)-3/4=-5/32-3/4=-29/32