cos(19π/6)+tan(16π/3)=?
问题描述：
cos(19π/6)+tan(16π/3)=?
答
所求式
=cos[(18π+π)/6]+tan[(15π+π)/3]
=cos(3π+π/6)+tan(5π+π/3)
=-cosπ/6+tanπ/3
=-√3/2+√3
=√3/2.