函数f(x)是以π/2为周期的奇函数,且f(π/3)=1,则f(-5π/6)=?

问题描述:

函数f(x)是以π/2为周期的奇函数,且f(π/3)=1,则f(-5π/6)=?

f(π/3+π/2)=f(π/3)=1
f(-5π/6)=-f(5π/6)=-1