(x+2y-1)(x-2y+1)—(x-2y-1)²等于什么

问题描述:

(x+2y-1)(x-2y+1)—(x-2y-1)²等于什么

原式=[x+(2y-1)][x-(2y-1)]-[(x-2y)-1]²
=x²-(2y-1)²-[(x-2y)²-2(x-2y)+1]
=x²-(4y²-4y+1)-(x²-4xy+4y²-2x+4y+1)
=x²-4y²+4y-1-x²+4xy-4y²+2x-4y-1
=4xy-8y²+2x-2