因式分解2p^2+4pq+2q^2-8t^2
问题描述：
因式分解2p^2+4pq+2q^2-8t^2
答
=2(p^2+2pq+q^2-4t^2)=2[(p+q)^2-(2t)^2]=2(p+q+2t)(p+q-2t)
因式分解2p^2+4pq+2q^2-8t^2
=2(p^2+2pq+q^2-4t^2)=2[(p+q)^2-(2t)^2]=2(p+q+2t)(p+q-2t)