已知x=(b+c)分之a,y=(c+a)分之b,z=(a+b)分之c,求:(1+x)分之x+(1+y)分之y+(1+z)分之z的值
问题描述：
已知x=(b+c)分之a,y=(c+a)分之b,z=(a+b)分之c,求:(1+x)分之x+(1+y)分之y+(1+z)分之z的值
答
1+x=1+a/(b+c)=（a+b+c)/(b+c)x/(1+x)=[a/(b+c)]/[(a+b+c)/(b+c)]=a/(a+b+c)同理：y/(1+y)=b/(a+b+c)z/(1+z)=c/(a+b+c)(1+x)分之x+(1+y)分之y+(1+z)分之z=a/(a+b+c)+b/(a+b+c)+c/(a+b+c)=（a+b+c)/(a+b+c)=1...