1-8x+16x^2=2-8x的详细解
问题描述：
1-8x+16x^2=2-8x的详细解
答
1+16X^2=2
16X^2=1
X^2=1/16
X=±1/4
答
1-8x+16x^2=2-8x
16x^2-1=0
(4x-1)(4x+1)=0
x=0.25或x=-0.25
答
1-8x+16x^2=2-8x
移项得：1-8x+16x^2-2+8x=0
合并同类项得：16x^2-1=0
即：16x^2=1
所以x^2=1/16
解得 x=±1/4
答
1-8x+16x^2=2-8x
16x^2-1=0
(4x+1)(4x-1)=0
所以4x+1=0，x=-1/4
或4x-1=0，x=1/4
答
1-8x+16x^2=2-8x
16x^2-1=0
(4x+1)(4x-1)=0
16(x+1/4)(x-1/4)=0
x=-1/4,x=1/4