3题七下因式分解2004x²-(2004²-1)x-2004x³-5x²+5x-4a^5-11a³+a

问题描述:

3题七下因式分解
2004x²-(2004²-1)x-2004
x³-5x²+5x-4
a^5-11a³+a

(2004x+1)(x-2004)

2004x²-(2004²-1)x-2004
=(x-2004)(2004x+1)
x³-5x²+5x-4
=x³-4x²-x²+4x+x-4
=x²(x-4)-x(x-4)+(x-4)
=(x-4)(x²-x+1)
a^5-11a³+10a
=a(a^4-11a^2+10)
=a(a^2-10)(a^2-1)
=a(a+1)(a-1)(a+√10)(a-√10)
最后一个是不是有问题???我改了 希望对你有帮助!!!

2004x²-(2004²-1)x-2004
=(2004x²-2004²x)+(x-2004)
=2004x(x-2004)+(x-2004)
=(x-2004)(2004x+1)
x³-5x²+5x-4
=x³-4x²-x²+5x-4
=x²(x-4)-(x-1)(x-4)
=(x-4)(x²-x+1)
a^5-11a³+a
=a(a^4-11a^2+1)
=a{[x²-(11+3√13)/2][x²-(11-3√13)/2]}
=a {x-√[(11+3√13)/2]} {x+√[(11+3√13)/2]} {x-√[(11+3√13)/2]} {x+ √[(11+3√13)/2]}