已知a=2-√2,b=2+√2,求(1)a²+2ab+b²/a³b+a²b²÷a²-b²/a²ab
问题描述:
已知a=2-√2,b=2+√2,求(1)a²+2ab+b²/a³b+a²b²÷a²-b²/a²ab
答
=(a+b)^2/a^2b(a+b)*a^2b/(a+b)(a-b)
=1/(a-b)
=1/-2√2=-√2/4