函数y=cosπ/2x×cosπ/2(x-1)的最小正周期
问题描述:
函数y=cosπ/2x×cosπ/2(x-1)的最小正周期
答
y=cosπ/2x×cosπ/2(x-1)=cosπ/2x cos(π/2x-π/2)=cosπ/2xsinπ/2x=1/2sinπx
故T=2π/π=2