(x-2)(x*x-6x-9)=x(x-5)(x-3),求6x的算术平方根

问题描述:

(x-2)(x*x-6x-9)=x(x-5)(x-3),求6x的算术平方根

(x-2)(x^2-6x-9)=x(x-5)(x-3)
x^3-6x^2-9x-2x^2+12x+18=x^3-8x^2+15x
-9x+12x+18=15x
12x=18
x=3/2
6x=9
算术平方根3

化简得X=6或0,那么6X的算术平方根为6或0

(x-2)(x*x-6x-9)=x(x-5)(x-3)
x^3-6x^2-9x-2x^2+12x+18=x^3-8x^2+15x
x=3/2
6x=9
6x的算术平方根为3

(x-2)(x*x-6x-9)=x(x-5)(x-3),
(x-2)[(x-3)²-18]=x(x-5)(x-3)
(x-2)(x-3)²-18(x-2)=x(x-5)(x-3)
(x-2)(x-3)²-x(x-5)(x-3)=18(x-2)
(x-3)[(x-2)(x-3)-x(x-5)]=18(x-2)
(x-3)[-5x+6+5x]=18(x-2)
x-3=3(x-2)
x-3=3x-6
-2x=-3
x=3/2
带入
√(6x)=√(9)=3