y-{y-2x+[5x-3(y+2x)+6y]},其中x= - 1/3,y= 1/8.
问题描述:
y-{y-2x+[5x-3(y+2x)+6y]},其中x= - 1/3,y= 1/8.
答
这道题很简单
y-{y-2x+[5x-3(y+2x)+6y]}
=y-[y-2x+(5x-3y-6x+6y)]
=y-[y-2x-x+3y]
=y-4y+3x
=3x-3y
=3×(-1/3)-3×1/8
=-11/8
答
y-{y-2x+[5x-3(y+2x)+6y]}
=y-[y-2x+(5x-3y-6x+6y)]
=y-[y-2x-x+3y]
=y-4y+3x
=3x-3y
=3×(-1/3)-3×1/8
=-11/8