9(2x-3)^2=4(2-x)^2

答

9(2x-3)^2=4(2-x)^2
(6x-9)²-(4-2x)²=0
(6x-9+4-2x)(6x-9-4+2x)=0
(4x-5)(8x-13)=0
x1=5/4,x2=13/8

答

(3*(2x-3)^2=(2*(2-x)^2
3*(2x-3)=2*(2-x) or 3*(2x-3)= - 2*(2-x)
6x-9=4-2x or 6x-9=-4+2x
8x=13 or 4x = 5
x=13/8 or x=5/4

答

（9（2x-3）^2）-(4（2-x）^2)=0
(3(2x-3)+2(2-x))(3(2x-3)-2(2-x))=0
(6x-9+4-2x)(6x-9-4+2x)=0
(4x-5)(8x-13)=0
x=5/4
x=13/8

答

9(2x-3)^2=4(2-x)^2
[3(2x-3)]^2-[2(x-2)]^2=0
(6x-9)^2-(2x-4)^2=0
(6x-9+2x-4)(6x-9-2x+4)=0
(8x-13)(4x-5)=0
x=13/8,x=5/4

答

9(2x-3)^2=4(2-x)^2
9(2x-3)^2-4(2-x)^2=0
(4X-5)(8X-13)=0
X=5/4,X=13/8

答

9(2x-3)^2=4(2-x)^2
9(2x-3)^2-4(2-x)^2=0
[3 (2x-3)+2(2-x)][3 (2x-3)-2(2-x)]=0
(6x-9+4-2x)(6x-9-4+2x)=0
(4x-5)(8x-13)=0
x1=5/4
x2=13/8