化简:sin(-4π/3)cos(-23π/6)tan25π/4
问题描述:
化简:sin(-4π/3)cos(-23π/6)tan25π/4
答
直接算啊
答
第一题:原式=0 第二题:无化简方向 sin(25pai/6)=sin(1pai/6)=0.5 cos(25pai/3)=cos(1pai/3)=0.5 tan(-25pai/4)= - tan(1pai
答
sin(-4π/3)cos(-23π/6)tan25π/4
=sin(2π-4π/3)cos(4π-23π/6)tan(25π/4-6π)
=sin(2π/3)cos(π/6)tan(π/4)
=√3/2*√3/2*1
=3/4