分式方程、不会阿
问题描述：
分式方程、不会阿
1.2/(1-x)+1=x/1+x
2.(x-2)/2x-1=1
3.1-1/(x-1)=-1
4.3/(1-y)=y/(y-1)-5
5.x/(x^2-2x+1)-2/(x-1)=0
6.1/x+5x/(x+3)=5
7.x^2/(X+4)=16/(x+4)
8.2/(x-2)-4x(x^2-4)=0
答
1.2/(1-x)+1=x/1+x
2（1+x）+1-x^2=x-x^2
2+2x+1=x
x=-3
2.(x-2)/2x-1=1
(x-2)=2x-1
x=-1
3.1-1/(x-1)=-1
2=1/(x-1)
x-1=1/2
x=3/2
4.3/(1-y)=y/(y-1)-5
-3=y-5y+5
4y=8
y=2
5.x/(x^2-2x+1)-2/(x-1)=0
x/(x^2-2x+1)=2/(x-1)
x=2x-2
x=2
6.1/x+5x/(x+3)=5
x+3+5x^2=5x^2+15x
14x=3
x=3/14
7.x^2/(X+4)=16/(x+4)
x^2=16
x=4
8.2/(x-2)-4x/(x^2-4)=0
2(x+2)-4x=0
2x+4=4x
2x=4
x=2
无解