y=sin(x-π/4)在[0,π]上的单调增区间是
问题描述:
y=sin(x-π/4)在[0,π]上的单调增区间是
答
y=sin(x-π/4),由于x∈[0,π],则x-π/4∈[-π/4,3π/4],则原函数的增区间是[0,3π/4].
y=sin(x-π/4)在[0,π]上的单调增区间是
y=sin(x-π/4),由于x∈[0,π],则x-π/4∈[-π/4,3π/4],则原函数的增区间是[0,3π/4].