一道分式方程,要过程,急!
问题描述：
一道分式方程,要过程,急!
5x/(x^2-10x+24)+(2x-5)/(x^2-x-12)=(7x-10)/x^2-6x+8
答
5x/(x^2-10x+24)+(2x-5)/(x^2-x-12)=(7x-10)/(x^2-6x+8)5x/(x-4)(x-6)+(2x-5)/(x-4)(x+3)=(7x-10)/(x-4)(x-2)方程两边同乘以(x-2)(x+3)(x-4)(x-6),得5x(x-2)(x+3)+(2x-5)(x-2)(x-6)=(7x-10)(x+3)(x-6)5x(x^2+x-6)+(2...