只要步骤完整,答案不管对错
只要步骤完整,答案不管对错
1.若多项式2X的4次方-3X³+CX²+7X-E能被X²+X-2整除,求C、E.
2.当K为何值时,关于X,Y的多项式KX²-2XY-3Y²+3X-5Y+2可以分解为两个一次因式的乘积?
3.求方程：XY=2X+2Y+7
4.{X²+3X/X²-4-(X+2)²/X²+X-6)÷3X+9/2-X
5.若2X²-5XY-3Y²=0,化简求值：3X²-XY/3X²+5XY-2Y²,和(X+Y/X-Y+4XY/Y²-X²)X²-4Y²/X²+3XY+2Y²
6.X²+2X+2/X+1+X²+8X+20/X+4=X²+4X+6/X+2+X²6X+12/X+3
7.化简：(Y-Z)²/（X-Y）（X-Z）+(Z-X)²/(Y-Z)(Y-X)+(X-Y)²/(Z-X)(Z-Y)
8.化简：A²-BC/(A+B)(A+C)+B²-CA/(B+C)(B+A)+C²-AB/(C+A)(C+B)
9.已知:X/A+Y/B+Z/C=1,A/X+B/Y+C/Z=0,求证：X²/A²+Y²/B²+Z²/C²=1
10.已知：A/B-C+B/C-A+C/A-B=0,求证：A/(B-C)²+B/(C-A)²+C/(A-B)²=0
其中 / 代表分号.
只要步骤完整,答案不论对错.谁答得题多而且有步骤就给他分数.
1.16x^4-3X³+CX²+7X-E=(X²+X-2)(16x^2+ax+b)
=16x^4+(a+16)x^3+(b+a-32)x^2+(b-2a)x-2b
-->a=-19,b=-31,C=-82,E=-62
2.KX²-2XY-3Y²+3X-5Y+2=(Kx+ay+1)(x+by+2)
=Kx^2+aby^2+(bK+a)xy+(2k+1)x+(2a+b)y+2
-->K=1,a=-3,b=1
3.xy-2y-2x+4=11-->(x-2)(y-2)=11-->x-2=11,y-2=1-->x=13,y=3
4.(X²+3X/X²-4-(X+2)²/X²+X-6)÷3X+9/2-X
=x/3+1/x^2-11/3x-4/3x^2-4/3x^3+1/3+9/2-x
=-2x/3-1/3x^2-11/3x-4/3x^3+29/6
5.2X²-5XY-3Y²=0,-->(2x+y)(x-3y)=0-->2x+y=0,x-3y=0
3X²-XY/3X²+5XY-2Y²=x(3x-y)/[(3x-y)(x+2y)]=x/(x+2y)=3/5或-1/3
(X+Y/X-Y+4XY/Y²-X²)X²-4Y²/X²+3XY+2Y²=感觉这题少了括号,应该为
((X+Y)/(X-Y)+4XY/(Y²-X²))X²-4Y²/(X²+3XY+2Y²)后面不知道怎么括号了.
6.-->-4/x=0无解
7.=[(y-z)^3+(z-x)^3+(x-y)^3]/[(x-y)(x-z)(y-z)]
8.好象又少括号.后面不想做了.乱