计算(2-i)(4+3i)
问题描述:
计算(2-i)(4+3i)
答
=(2-1)·+(2-)·3i
=8-4i+6i+3
=11+2i前面还没编辑完按错了就发出去了 原式=(2-i)·4+(2-i)·3i =8-4i+6i+3 =11+2i