7(2x-1)-3(4x-1)+5(4x+2)-28=0

问题描述:

7(2x-1)-3(4x-1)+5(4x+2)-28=0

7(2x-1)-3(4x-1)+5(4x+2)-28=0
14x-7-12x+3+20x+10-28=0
14x-12x+20x=7-3-10+28
22x=14
x=14/22
x=7/11